Hi
I have a Lotus User ID password in which I need to crack open.
Have no idea of the version nor password length since it was used a long time ago in the office.
The problem is my hashing results with "lotus2john.py" is nowhere close to the examples given in the page:
lotus2john.py user.id
user.id:6247FE2575XXXXXXXXEB73CF63EECEB719XXXXXXXXF2A202FE23A29BXXXXXX9BA06DBC792191XXXXXX86697B14D36F394C67XXXXXXXX668F
Hopefully someone can help.
I have a Lotus User ID password in which I need to crack open.
Have no idea of the version nor password length since it was used a long time ago in the office.
The problem is my hashing results with "lotus2john.py" is nowhere close to the examples given in the page:
lotus2john.py user.id
user.id:6247FE2575XXXXXXXXEB73CF63EECEB719XXXXXXXXF2A202FE23A29BXXXXXX9BA06DBC792191XXXXXX86697B14D36F394C67XXXXXXXX668F
Hopefully someone can help.